Integrand size = 15, antiderivative size = 81 \[ \int \frac {(2+b x)^{5/2}}{x^{5/2}} \, dx=5 b^2 \sqrt {x} \sqrt {2+b x}-\frac {10 b (2+b x)^{3/2}}{3 \sqrt {x}}-\frac {2 (2+b x)^{5/2}}{3 x^{3/2}}+10 b^{3/2} \text {arcsinh}\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {2}}\right ) \]
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Time = 0.01 (sec) , antiderivative size = 81, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.267, Rules used = {49, 52, 56, 221} \[ \int \frac {(2+b x)^{5/2}}{x^{5/2}} \, dx=10 b^{3/2} \text {arcsinh}\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {2}}\right )+5 b^2 \sqrt {x} \sqrt {b x+2}-\frac {2 (b x+2)^{5/2}}{3 x^{3/2}}-\frac {10 b (b x+2)^{3/2}}{3 \sqrt {x}} \]
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Rule 49
Rule 52
Rule 56
Rule 221
Rubi steps \begin{align*} \text {integral}& = -\frac {2 (2+b x)^{5/2}}{3 x^{3/2}}+\frac {1}{3} (5 b) \int \frac {(2+b x)^{3/2}}{x^{3/2}} \, dx \\ & = -\frac {10 b (2+b x)^{3/2}}{3 \sqrt {x}}-\frac {2 (2+b x)^{5/2}}{3 x^{3/2}}+\left (5 b^2\right ) \int \frac {\sqrt {2+b x}}{\sqrt {x}} \, dx \\ & = 5 b^2 \sqrt {x} \sqrt {2+b x}-\frac {10 b (2+b x)^{3/2}}{3 \sqrt {x}}-\frac {2 (2+b x)^{5/2}}{3 x^{3/2}}+\left (5 b^2\right ) \int \frac {1}{\sqrt {x} \sqrt {2+b x}} \, dx \\ & = 5 b^2 \sqrt {x} \sqrt {2+b x}-\frac {10 b (2+b x)^{3/2}}{3 \sqrt {x}}-\frac {2 (2+b x)^{5/2}}{3 x^{3/2}}+\left (10 b^2\right ) \text {Subst}\left (\int \frac {1}{\sqrt {2+b x^2}} \, dx,x,\sqrt {x}\right ) \\ & = 5 b^2 \sqrt {x} \sqrt {2+b x}-\frac {10 b (2+b x)^{3/2}}{3 \sqrt {x}}-\frac {2 (2+b x)^{5/2}}{3 x^{3/2}}+10 b^{3/2} \sinh ^{-1}\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {2}}\right ) \\ \end{align*}
Time = 0.11 (sec) , antiderivative size = 63, normalized size of antiderivative = 0.78 \[ \int \frac {(2+b x)^{5/2}}{x^{5/2}} \, dx=\frac {\sqrt {2+b x} \left (-8-28 b x+3 b^2 x^2\right )}{3 x^{3/2}}-10 b^{3/2} \log \left (-\sqrt {b} \sqrt {x}+\sqrt {2+b x}\right ) \]
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Time = 0.08 (sec) , antiderivative size = 63, normalized size of antiderivative = 0.78
method | result | size |
meijerg | \(-\frac {15 b^{\frac {3}{2}} \left (\frac {32 \sqrt {\pi }\, \sqrt {2}\, \left (-\frac {3}{8} b^{2} x^{2}+\frac {7}{2} b x +1\right ) \sqrt {\frac {b x}{2}+1}}{45 x^{\frac {3}{2}} b^{\frac {3}{2}}}-\frac {8 \sqrt {\pi }\, \operatorname {arcsinh}\left (\frac {\sqrt {b}\, \sqrt {x}\, \sqrt {2}}{2}\right )}{3}\right )}{4 \sqrt {\pi }}\) | \(63\) |
risch | \(\frac {3 b^{3} x^{3}-22 b^{2} x^{2}-64 b x -16}{3 x^{\frac {3}{2}} \sqrt {b x +2}}+\frac {5 b^{\frac {3}{2}} \ln \left (\frac {b x +1}{\sqrt {b}}+\sqrt {b \,x^{2}+2 x}\right ) \sqrt {x \left (b x +2\right )}}{\sqrt {x}\, \sqrt {b x +2}}\) | \(82\) |
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Time = 0.23 (sec) , antiderivative size = 123, normalized size of antiderivative = 1.52 \[ \int \frac {(2+b x)^{5/2}}{x^{5/2}} \, dx=\left [\frac {15 \, b^{\frac {3}{2}} x^{2} \log \left (b x + \sqrt {b x + 2} \sqrt {b} \sqrt {x} + 1\right ) + {\left (3 \, b^{2} x^{2} - 28 \, b x - 8\right )} \sqrt {b x + 2} \sqrt {x}}{3 \, x^{2}}, -\frac {30 \, \sqrt {-b} b x^{2} \arctan \left (\frac {\sqrt {b x + 2} \sqrt {-b}}{b \sqrt {x}}\right ) - {\left (3 \, b^{2} x^{2} - 28 \, b x - 8\right )} \sqrt {b x + 2} \sqrt {x}}{3 \, x^{2}}\right ] \]
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Time = 4.57 (sec) , antiderivative size = 88, normalized size of antiderivative = 1.09 \[ \int \frac {(2+b x)^{5/2}}{x^{5/2}} \, dx=b^{\frac {5}{2}} x \sqrt {1 + \frac {2}{b x}} - \frac {28 b^{\frac {3}{2}} \sqrt {1 + \frac {2}{b x}}}{3} - 5 b^{\frac {3}{2}} \log {\left (\frac {1}{b x} \right )} + 10 b^{\frac {3}{2}} \log {\left (\sqrt {1 + \frac {2}{b x}} + 1 \right )} - \frac {8 \sqrt {b} \sqrt {1 + \frac {2}{b x}}}{3 x} \]
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Time = 0.32 (sec) , antiderivative size = 96, normalized size of antiderivative = 1.19 \[ \int \frac {(2+b x)^{5/2}}{x^{5/2}} \, dx=-5 \, b^{\frac {3}{2}} \log \left (-\frac {\sqrt {b} - \frac {\sqrt {b x + 2}}{\sqrt {x}}}{\sqrt {b} + \frac {\sqrt {b x + 2}}{\sqrt {x}}}\right ) - \frac {8 \, \sqrt {b x + 2} b}{\sqrt {x}} - \frac {2 \, \sqrt {b x + 2} b^{2}}{{\left (b - \frac {b x + 2}{x}\right )} \sqrt {x}} - \frac {4 \, {\left (b x + 2\right )}^{\frac {3}{2}}}{3 \, x^{\frac {3}{2}}} \]
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Time = 6.11 (sec) , antiderivative size = 91, normalized size of antiderivative = 1.12 \[ \int \frac {(2+b x)^{5/2}}{x^{5/2}} \, dx=-\frac {{\left (30 \, b^{\frac {3}{2}} \log \left ({\left | -\sqrt {b x + 2} \sqrt {b} + \sqrt {{\left (b x + 2\right )} b - 2 \, b} \right |}\right ) - \frac {{\left (60 \, b^{3} + {\left (3 \, {\left (b x + 2\right )} b^{3} - 40 \, b^{3}\right )} {\left (b x + 2\right )}\right )} \sqrt {b x + 2}}{{\left ({\left (b x + 2\right )} b - 2 \, b\right )}^{\frac {3}{2}}}\right )} b}{3 \, {\left | b \right |}} \]
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Timed out. \[ \int \frac {(2+b x)^{5/2}}{x^{5/2}} \, dx=\int \frac {{\left (b\,x+2\right )}^{5/2}}{x^{5/2}} \,d x \]
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